Question 1163783
<pre>
 0 <= θ < 2 pi. What is -6 sin θ = 3 square root of 3.

{{{-6sin(theta)}}}{{{""=""}}}{{{3sqrt(3)}}}

Divide both sides by -6

{{{sin(theta)}}}{{{""=""}}}{{{3sqrt(3)/(-6)}}}

{{{sin(theta)}}}{{{""=""}}}{{{-sqrt(3)/2}}}

The sine is positive only in QIII and QIV

{{{theta}}}{{{""=""}}}{{{4pi/3}}}{{{or}}}{{{theta}}}{{{""=""}}}{{{5pi/3}}}

Edwin</pre>