Question 1163729
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A takes 24 days for the whole job, so A can do *[tex \Large \frac{1}{24}] of the job in one day.  Likewise B can do *[tex \Large \frac{1}{30}] of the job in one day.  Working together they can do *[tex \Large \frac{1}{24}\ +\ \frac{1}{30}\ =\ \frac{3}{40}] of the job in 1 day.  So in 8 days, they accomplish *[tex \Large \frac{24}{40}\ =\ \frac{3}{5}] of the job, leaving C to finish *[tex \Large \frac{2}{5}] of the job in 6 days.  If C takes 6 days to accomplish *[tex \Large \frac{2}{5}] of the job, then C can do *[tex \Large \(\frac{2}{5}\)\(\frac{1}{6}\)\ =\ \frac{1}{15}] of the total job in one day, so C can accomplish the whole job in *[tex \Large 15] days.

								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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