Question 1163722
Bob and Moe set off at the same time on a 30 km walk for charity. 
Bob walks 1.4 km/h faster than Moe,
<pre>
Let Moe's rate be r
Then Bob's rate is r+1.4

Make this chart:

                  Distance       Rate      Time
Moe on the 30 km     30           r       30/r
------------------------------------------------------
Bob on the 30 km     30         r+1.4   30/(r+1.4) 
</pre>
but [Bob] stops for 20 min on route. 
<pre>
That's 1/3 of an hr.
                                      
                 Distance      Rate      Time
Moe                30           r       30/r
------------------------------------------------------
Bob on the 30 km   30         r+1.4   30/(r+1.4) 
Bob's stop          0           0       1/3 h  
--------------------------------------------------------
</pre>
Even with the delay, Bob finishes 2 hours ahead of Moe.
<pre>
{{{(matrix(3,1,"Bob's","total","time"))}}}{{{""=""}}}{{{(matrix(3,1,"Moe's", total, time))}}}{{{""-""}}}{{{2}}}     

{{{30/(r+1.4)+1/3}}}{{{""=""}}}{{{30/r-2}}}

{{{90r+r(r+1.4) = 90(r+1.4)-6r(r+1.4)}}}

Solve that (you can use the quadratic formula if you
can't factor.

The approximate rate for Moe is about ????????? km/h

You solve the equation.
</pre>
how long in hours did it take for Moe to finish the walk?
<pre>
That's a trick question.  Since Bob finished 2 hours 
ahead of Moe, Moe finished 2 hours later. lol.

Hmmm.  I took it to mean how long after Bob finished did it
take for Moe to finish.   But maybe you want Moe's WHOLE
time.  If so, divide 30 by what you got for r.

Edwin</pre>