<PRE><B>Question 1163708</B>
&lt;br&gt;
P(A successful) = 2/3 = 8/12&lt;br&gt;
P(B successful) = 1/2 = 6/12&lt;br&gt;
P(A or B (or both) successful) = 3/4 = 9/12&lt;br&gt;
P(A successful but not B) = 9/12 - 6/12 = 3/12&lt;br&gt;
P(B successful but not A) = 9/12 - 8/12 = 1/12&lt;br&gt;
P(only one team successful) = 3/12 + 1/12 = 4/12&lt;br&gt;
P(B successful, given that only one team was successful) = (1/12)/(4/12) = 1/4&lt;br&gt;
ANSWER: 1/4&lt;br&gt;
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