Question 1163701
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Please post your questions by TYPING, using standard keyboard characters.  Whatever you are doing, all the numbers are getting doubled, making it hard to see what the real question is.<br>
johny has a coin collection. he has {{{cross(9898)}}} 98 coins in all. he has {{{cross(33)}}} 3 times as many pennies as dimes. he has {{{cross(44)}}} 4 more dimes than nickles, and {{{cross(66)}}} 6 less dimes than quarters.<br>
Read the given information and take a bit of time to find a way to write expressions for the numbers of pennies, nickels, dimes, and quarters as easily as possible using a single variable.<br>
The number of pennies is 3 times the number of dimes:  x = number of dimes; 3x = number of pennies.<br>
He has 4 more dimes than nickels, so the number of nickels is 4 less than the number of dimes: x-4 = number of nickels.<br>
He has 6 fewer dimes than quarters, so the number of quarters is 6 more than the number of dimes: x+6 = number of quarters.<br>
Now that you have expressions in terms of a single variable for the numbers of each coin, write and solve the equation that says the total number of coins is 98:<br>
{{{(x)+(3x)+(x-4)+(x+6) = 98}}}
{{{6x+2 = 98}}}<br>
I'll let you finish from there....<br>