Question 1163680
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<H3>Part &nbsp;(a):  &nbsp;&nbsp;to double</H3>

<pre>
200000 = {{{100000*e^(0.0475*t)}}}


{{{200000/100000}}} = {{{e^(0.0475*t)}}}


2 = {{{e^(0.0475*t)}}}


It is your basic formula for doubling.


Take natural logarithm of both sides


ln(2) = 0.0475*t


t = {{{ln(2)/0.0475}}} = 14.59  years.    <U>ANSWER</U>
</pre>

This case is completed.


For other cases do the same. &nbsp;&nbsp;Part &nbsp;(a) &nbsp;is your &nbsp;TEMPLATE &nbsp;for other parts.


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To see the theory and many other similar solved problems, &nbsp;see my lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/logarithm/Problems-on-continuously-compound-accounts.lesson>Problems on continuously compounded accounts</A> 

in this site.


Consider this lesson as your textbook, handbook, tutorials and (free of charge) home teacher.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this online textbook under the topic "<U>Logarithms</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.



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