Question 1163660
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In this problem, the work done is the product of the distance and the horizontal component of the force.


The distance is 153 m horizontally.

The horizontal component of the force is 225*cos(65°)  newtons.


Thus the work is  153*225*cos(65°) newtons*meter = 153*225*cos(65°) joules.


I leave computations to you.
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Solved.


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For similar problems, see the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Vectors/Using-vectors-to-solve-problems-in-Mechanics%3A-Force.lesson>Using vectors to solve problems in Mechanics: Force</A> 

in this site.



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