Question 1163606
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     *[illustration ThetaAnd2ThetaOnUnitCircle.jpg]


The measure of CA and CP are each 1.  *[tex \Large \cos\theta] is the measure of CD divided by the measure of CA, or just CD, hence the *[tex \Large x] coordinate of point A is *[tex \Large \cos\theta].  Similarly, the measure of AD and therefore *[tex \Large \sin\theta] is the *[tex \Large y]-coordinate of A.


Using the same rationale it is elementary to show that the coordinates of P are *[tex \Large \(\sin 2\theta,\cos\theta\)].


I'm still working on writing out the rest.  Send me a note and I'll send it back perhaps tonight or tomorrow AM.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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