Question 105382
Since {{{x+y=12}}} and {{{y=2x}}},

then,,,

{{{x+2x=12}}}
{{{3x=12}}}
{{{x=4}}}


Solving for y,

{{{y=2x}}}
{{{y=2*4}}}
{{{y=8}}}


Thus, {{{x=4}}} and {{{y=8}}}


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