Question 1163495
<pre>
Since Amy goes 6 m/s and Betty goes 5 m/s, the curved arc distance between
them shrinks by 6-5 = 1 m/s, with Amy gaining on Betty. 

Amy gains on Betty 1 arc meter per second.

Amy starts out 100 arc meters behind Betty
So Amy will catch up to Betty the first time in 100 seconds.
Thereafter, Amy will catch up to Betty every 200 seconds.

There are 16∙60=960 seconds in 16 minutes.

Let n be the number of catch-ups Betty will make after the first one.

So 100 + n*200 <= 960
          200n <= 860
             n <= 4.3

So Betty will make 4 more catchups after the first, or 5 catch-ups.

Answer: 5

Edwin</pre>