Question 1163435
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Let the width be x; then the length is 6x-4.<br>
The area (length times width) is 20 square inches:<br>
{{{x(6x-4) = 20}}}
{{{6x^2-4x = 20}}}
{{{6x^2-4x-20 = 0}}}
{{{3x^2-2x-5 = 0}}}
{{{(3x-5)(x+1) = 0}}}<br>
{{{x = 5/3}}} or {{{x = -1}}}<br>
Obviously the negative solution makes no sense in the problem....<br>
So x = 5/3; 6x-4 = 10-4 = 6; the area is 6(5/3) = 20.<br>
ANSWER: The dimensions of the rectangle are 5/3 inches by 6 inches.<br>
Convert the 5/3 to a decimal rounded to the nearest hundredth if you need to....<br>