Question 1163432
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In a two digit number the tens digit is 3 more than the ones digit. If the digits are reversed 
the difference between the two numbers is 27. Find the number.
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<pre>

Let "a" be the tens digit of the 2-digit number, and

let "b" be the ones digit of the number.


Then the number is

    n = 10a + b,         (1)


while the reversed digit number is 

    m = 10b + a.         (2)


Since the tens digit is 3 more than the ones, the original number is greater than the reversed one. 
Hence, according to the condition, the original number is 27 more than the reversed number.  It means

    (10a+b) - (10b+a) = 27,    or

    9a - 9b = 27,

    9*(a-b) = 27,

    a-b     = 27/9 = 3.    (3)


Notice that it is exactly the FIRST condition given in the problem.


Thus in the problem the first condition IS NOT INDEPENDENT: it is just contained in the second condition.


Surely, <U>it is the problem's FAULT</U>, which leads to the fact that the final solution is not unique.


Any of the numbers  41, 52, 63, 74, 85, 96  satisfies the problem's condition.      <U>ANSWER</U>
</pre>

Solved.


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Today I observe a FLOW of problems, part of which have curved formulation, while another part are simply INCORRECT.


It becomes really interesting to me, who creates these heavily sick problems and from which GARBAGE BOX the visitors recover them.



Probably, the time came to issue this WARNING:


If I will see the flow of nonsensical or heavy sick problems, I will collect their links

and write to the MANAGERS of this project asking them take PERSONAL measures against such visitors.