Question 1163396
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<pre>

Exponential rate of decay per year "r" remains THE SAME during the entire decay process 

(i.e. FOREVER, or, more precisely, until the last radioactive atom decayed :-).


It is equal to  r = {{{1.5^(-1)}}} = {{{1/1.5}}} = {{{1/((3/2))}}} = {{{2/3}}} = 0.666666...  or  66.6666%  of the mass per year.



By the way, when you formulate a problem like this one, you should tell in your question, which rate of decay do you mean:

    exponential coefficient of decay or linear coefficient at the given time.



These are two different values and two different conceptions.


Without clarification, the meaning of the question is dark / unclear.
</pre>


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What the tutor ankor@dixie-net.com wrote in his response, &nbsp;was not an answer to your question.


It was something &nbsp;&nbsp;<U>V E R Y &nbsp;&nbsp;different</U>. &nbsp;&nbsp;It was about the remained mass amount after 2 years.



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On radioactive decay problems, &nbsp;see the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/logarithm/Radioactive-decay-problems.lesson>Radioactive decay problems</A> 

in this site.