Question 1163258
.
<pre>

From the condition, you have

    {{{(2/5)*A}}} = {{{(2/3)B}}}.    (1)


Multiply both sides by 3*5 = 15.   You will get

    6A = 10B,   or

    3A = 5B.         (2)


You have also second equation
    
    A + B = 4800.    (3)


Multiply its both sides by 3.  You will get

    3A + 3B = 3*4800 = 14400.


In the left side, replace 3A by 5B, based on equation (2).  You will get

    5B + 3B = 14400,  or

    8B      = 14400,

     B      = 14400/8 = 1800.


So, the amount B is just found: it is 1800 dollars.


The last step is to find A. For it, subtract 1800 from 4800

    A = 4800 - 1800 = 3000 dollars.


<U>ANSWER</U>.  A has $3000;  B has $1800.
</pre>


-------------
comment from student: Why did you multiply equation (3) by 3 ?
-------------



<U>My response</U> :  Good question, thanks for asking.


<pre>
    I multiply equation (3) by 3  in order for to have this term " 3A ", which I later replace by  " 5B ".


    My secret goal is to get an equation for one unknown " B " only, and for it I make all these transformations.
</pre>


Is everything clear to you now ?


If you still have questions, do not hesitate to post them to me . . . 



Have a nice day (!)



-------------
comment from student: &nbsp;&nbsp;How did you get 3A = 5B from 6A = 10B ?
-------------



<U>My response</U> :  &nbsp;&nbsp;I divided both sides of the equation  &nbsp;6A = 10B  &nbsp;by &nbsp;2.