Question 1163251

Pls help me. Given that logx^256=2 find log8^(<s>1over</s> lower x) Thanks
<pre>If you meant: {{{matrix(1,3, log (x, (256)), "=", 2)}}}, then READ on!
{{{matrix(1,3, x^2, "=", 256)}}} ------ Converting to EXPONENTIAL form
{{{matrix(2,3, x^2, "=", 16^2, x, "=", 16)}}} ------ EXPONENTS are equal and so are the BASES


Now, what's needed is: {{{log (x, (8))}}}. If it's {{{log (8, (x))}}}, then you're on your own, but should be able to figure it out, if you follow below!
{{{log (16, (8))}}} -------- Substituting 16 for x
{{{matrix(1,3, c, "=", log (16, (8)))}}} --- Letting the value of {{{log (16, (8))}}} be "c." 
{{{matrix(1,3, 16^c, "=", 8)}}} -------- Converting to EXPONENTIAL form
{{{matrix(2,3, (2^4)^c, "=", 2^3, 2^(4c), "=", 2^3)}}} 
4c = 3 ------ BASES are equal and so are the EXPONENTS
{{{highlight_green(matrix(1,7, "c,", or, log (x, (8)), "=", log (16, (8)), "=", highlight(3/4)))}}}</pre>