Question 1163160
Find the seventh term of (x^2-2)^9
<pre>To find a SPECIFIC TERM of a binomial expansion, we use the formula: {{{(a + b)^n = "" [n]C[r - 1](a)^(n - (r - 1))(b)^(r - 1)}}},      
                                                                     where: {{{matrix(4,3, r, "=", 7, n, "=", 9, a, "=", x^2, b, "=", - 2)}}}
We then get: 7<sup>th</sup> term of {{{highlight_green(matrix(1,2, (x^2 - 2)^9, matrix(4,2, "=", "" [9]C[7 - 1](x^2)^(9 - (7 - 1))(- 2)^(7 - 1),
"=", "" [9]C[6](x^2)^3(- 2)^6,
"=", 84 * x^6 * 64,
"=", highlight("5,376"x^6))))}}}