Question 1163142
The sum of the ages of two brothers is 38 years.  4 years ago the age of the Elder brother was the square of the younger Brothers age. Find their ages.
----------------
e + y = 38 now
4 years ago, e + y = 30
-----------
e + y = 30
e = y^2
---> 5 & 25 then
9 & 29 now
===============
The hard way:
e + y = 30
e = y^2
y^2 + y - 30 = 0
(y+6)*(y-5) = 0
y = 5
etc