Question 1163122
<pre>
Instead of doing your problem for you, I'll do one exactly like it with
different numbers.  I'll do this one instead:

An urn contains x red balls and y green balls. if a ball is taken at random
from the urn, the probability that it is red is 3/5. Write down an equation
connecting x and y. if there had been 6 more red balls, the probability
would have been 9/13. find x and y.

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An urn contains x red balls and y green balls. if a ball is taken at random
from the urn, the probability that it is red is 3/5.

{{{x/(x+y)=3/5}}}
{{{5x=3x+3y}}}
{{{2x=3y}}}
{{{x=3y/2}}}

If there had been 6 more red balls, the probability would have been 9/13. find x and y.

{{{(x+6)/(x+y+6)=9/13}}}
{{{13x+78=9x+9y+54}}}
{{{4x-9y=-24}}}

Substituting 3y/2 for x in

{{{4x-9y=-24}}}
{{{4(3y/2)-9y=-24}}}
{{{6y-9y=-24}}}
{{{-3y=-24}}}
{{{y=8}}}

Substituting 8 for y in

{{{x=3y/2}}}
{{{x=3(8)/2}}}
{{{x=24/2}}}
{{{x=12}}}

Edwin</pre>