Question 1163114
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<pre>

Let x be the rate (in miles per hour) going to friend's home.

Then the speed going back is (x+10) mph.


The time going to there is  {{{300/x}}}  hours.

The time going back is  {{{300/(x+10)}}}  hours.


The "time" equation is  


    {{{300/x}}} - {{{300/(x+10)}}} = 1   hour.


The solution/(the answer) is just seen from here:  x = 50 mph.


To get formal algebra solution, multiply both sides by x*(x+10).  You will get


    300*(x+10) - 300x = x*(x+10)

    300x + 3000 - 300x = x^2 + 10x

    x^2 + 10x - 3000 = 0

    (x-50)*(x+60) = 0

    and  x= 50 is the only meaningful positive solution.


<U>ANSWER</U>.  The rate going to friend's home was  50 mph.


<U>CHECK</U>.   {{{300/50}}} - {{{300/(50+10)}}} = 6 - 5 = 1 hour.   ! Correct !
</pre>

Solved.


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Using &nbsp;"time" &nbsp;equation is a &nbsp;STANDARD &nbsp;method of solving such problems.

From this lesson, &nbsp;learn on how to write, &nbsp;how to use and how to solve a &nbsp;"time" &nbsp;equation.


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