<PRE><B>Question 1163107</B>
You can first use the distance formula definition of parabola having focus (3,0) and directrix (-3/2,y), here y NOT being the same as in point P.  Simplify as you like, and then find the missing coordinate of point P.



FINDING THE EQUATION

{{{(x-3)^2+(y-0)^2=(x-(-3/2))^2+(y-y)^2}}}

{{{(x-3)^2+y^2=(x+3/2)^2}}}

{{{x^2-6x+9+y^2=x^2+(6/2)x+9/4}}}

{{{-6x+9+y^2=3x+9/4}}}

{{{-9x+y^2+9-9/4=0}}}

{{{-36x+4y^2+36-9=0}}}

{{{-36x+4y^2+27=0}}}

{{{highlight_green(4y^2=36x-27)}}}


Now, for point P(2,y), what is (or are) the value of y when x is 2 ?</PRE>