Question 1163047
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ FV\ =\ Pe^{rt}]


If the money is doubled, then *[tex \Large \frac{FV}{P}\ =\ 2],


So *[tex \Large e^{rt}\ =\ 2], but *[tex \Large r\ =\ 0.065] so solve


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ e^{0.065t}\ =\ 2]


for *[tex \Large t].


Hint:  Take the natural log of both sides.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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