Question 1163044
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(2)  To solve problem (2), use the facts  1 foot = 12 inches; 1 inch = 2.54 cm.




(5)  The distance "how far"  = {{{(at^2)/2}}},  where "a" is the acceleration  a = {{{v/t}}} = {{{60/20}}} = 3 m/s^2.


     Thus  "how far" = {{{(3*20^2)/2}}} = {{{(3*400)/2}}} = 3*200 = 600 meters.


     Interesting, that this distance is the same as if you multiply the average speed of 30 m/s by the time 20 seconds


        "how far" = {{{V[average]*t}}} = 30 m/s * 20 s = 600 meters.


    It is the same as  "how far" = {{{v^2/(2t)}}}.


    Memorize these formulas and the method of solution (!)
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In the future, do not post more than 1 problem / question per post.