Question 108014

solve first {{{x^2 - 3x - 4 = 0}}}, then take only values for {{{x}}} where {{{x^2 - 3x - 4 > 0}}}


*[invoke internal_equation "x^2-3x-4=0"]


as you can see, we will take all values for {{{x > 4}}}
solution:
[{{{4}}},{{{infinity}}})