Question 107973
{{{SA=2lw+2lh+2wh}}} Start with the given equation




{{{0=2lw+2lh+2wh-SA}}}Subtract SA from both sides



{{{-2lh=2lw+2wh-SA}}} Subtract 2lh from both sides



{{{-2lh-2wh=2lw-SA}}} Subtract 2wh from both sides



{{{-2h(l+w)=2lw-SA}}} Factor out the GCF -2h from the left side



{{{h=(2lw-SA)/-2(l+w)}}} Divide both sides by -2(l+w) to isolate h



{{{h=(SA-2lw)/2(l+w)}}} Simplify