<PRE><B>Question 1162878</B>
Find an equation for the line perpendicular to 3x+27y=108
and goes through the point (5,10).
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Find the slope of the given line, m1.
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The slope of lines perpendicular have a slope of -1/m1.
Call it m2
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Use y-y1 = m2*(x-x1) where (x1,y1) is the given point.
solve for y
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