Question 1162689
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The faster pipe can fill the tank in 6 hours; in the 2 hours it works, it fills 1/3 of the tank.  So the slower pipe fills 2/3 of the tank.<br>
Since the slower pipe can fill the whole tank in 8 hours, it can fill 2/3 of the tank is 2/3 of 8 hours, which is 16/3 hours, or 5 1/3 hours.<br>
So the additional amount of time it takes the slower pipe to fill the tank after the two pipes work together for 2 hours is 3 1/3 hours.<br>
ANSWER: The slower pipe takes 3 1/3 hours to finish filling the tank after the two pipes work together for 2 hours.<br>
Algebraically...<br>
The faster tank fills 1/6 of the tank in 1 hour; the slower fills 1/8 in 1 hour.<br>
The faster pipe working for 2 hours, plus the slower pipe working for 2+x hours, fills the whole tank:<br>
{{{2(1/6)+(2+x)(1/8) = 1}}}<br>
You can solve from there....<br>