Question 107912
Start with the given system

{{{3x+3y=5}}}
{{{y=-x}}}




{{{3x+3(-x)=5}}}  Now plug in {{{y=-x}}}. In other words, replace each {{{y}}} with {{{-x}}}. Notice we've eliminated the {{{y}}} variables. So we now have a simple equation with one unknown.



{{{3x-3x=5}}} Multiply



{{{0x=5}}} Combine like terms on the left side



{{{0=5}}} Simplify


Since this equation is <font size=4><b>never</b></font> true for any x value, this means there are no solutions.


So the system is <a href=http://www.algebra.com/algebra/homework/coordinate/lessons/Types-of-systems-inconsistent-dependent-independent.lesson>inconsistent</a>