Question 1162641
<pre>
The focus is at the midpoint between the two foci, which is (5,2)

c = the distance from the center to the focus, so c = 3

c² = a²-b² 
3² = a²-4²
 9 = a²-16
25 = a²
 5 = a

Equation:

{{{(x-h)^2/a^2+(y-k)^2/b^2=1}}}

{{{(x-5)^2/5²+(y-2)^2/3^2=1}}}

{{{(x-5)^2/25+(y-2)^2/9=1}}}

{{{drawing(400,400,-1,11,-4,8,grid(1),

circle(8,2,.2),circle(2,2,.2),circle(5,2,.2),
arc(5,2,10,8) )}}}

Edwin</pre>