Question 1162589
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If entity A can finish one complete job in *[tex \Large x] time periods, and entity B can finish the same job i *[tex \Large y] time periods, then A can complete *[tex \Large \frac{1}{x}] of the job in one time period and B can complete *[tex \Large \frac{1}{y}] of the job in one time period.  So, working together, A and B can complete *[tex \Large \frac{1}{x}\ +\ \frac{1}{y}\ =\ \frac{x\,+\,y}{xy}] of the job in one time period. And therefore, working together, the two entities can complete the job in *[tex \Large \frac{xy}{x\,+\,y}] time periods.


In this case, *[tex \Large x\ =\ y\,+\,8] and *[tex \Large \frac{xy}{x\,+\,y}\ =\ 9], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(y\,+\,8)y}{2y\,+\,8}\ =\ 9]


Solve for *[tex \Large y]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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