Question 107694
You gave these info:


{{{-15x+3y=6}}} and {{{y=2+5x}}}


In {{{-15x+3y=6}}}, there are two variable available on the left-hand side---{{{x}}} and {{{y}}}.


While on {{{y=2+5x}}}, There's just one variable({{{y}}}) on the left-hand side...


If we substitute {{{y=2+5x}}} to {{{-15x+3y=6}}},


THe equation obtained is...

{{{-15x+3(2+5x)=6}}}
{{{-15x+(3*2+3*5x)=6}}}
{{{-15x+(9+15x)=6}}}
{{{-15x+(15x+9)=6}}}
{{{-15x+15x+9=6}}}
{{{(-15x+15x)+9=6}}}
{{{0+9=6}}}
{{{9=6}}}    What?!?!?  



The equations produced a FALSe statement (we all know that 9 can NEVER be equal to 6). Therefore, there is no solution.


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