Question 1162443
<br>
{{{A = P(1+r)^n}}}<br>
A = future value
P = beginning principal
r = periodic interest rate
n = number of compounding periods<br>
A is what we need to find
P is $1000
r is 1/12 of 10% (1/12 of 0.10), since the period is monthly
n is 4*12 = 48, the number of months (periods) in 4 years<br>
{{{A = 1000(1+.10/12)^48}}}<br>
Use a calculator....<br>