Question 1162414
{{{y=(2/3)x-1}}}

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Line in the plane parallel to that one is of some form {{{y=(2/3)x+b}}}.


Your given point to include in this parallel line is  (2,-3).
{{{b=y-(2/3)x}}}
{{{b=-3-(2/3)*2}}}
{{{b=-3-4/3}}}
{{{b=-9/3-4/3}}}
{{{b=-13/3}}}
or {{{b=-4&1/3}}}


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{{{highlight(y=(2/3)x-4&1/3)}}}