Question 1162375
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C is the midpoint of BE, so B, C, and E are collinear.<br>
Then, because AB is parallel to CD, angles ABC and DCE are congruent.<br>
Then, since AB is congruent to CD and BC is congruent to CE, triangles ABC and DCE are congruent by SAS.<br>
Triangles ABC and DCE are congruent, and angles BCA and CED are congruent.<br>
The sum of angles ABC, BCA, and CAB is 180 degrees; the sum of angles BCA, ACD, and DCA is 180 degrees.<br>
Therefore, angles ACD and CDA are congruent.<br>
And, therefore, AC and DE are parallel.<br>