Question 1162282
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Under the given condition, there are only three possible outcomes


    (1,1), (2,1) and (1,2).


So, the space of events in this case consists of 3 events with equal probability  {{{1/3}}}  of each.


Of them, there is only one favorable outcome (1,1).


Thus the answer to the problem's question is  {{{1/3}}}.
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Solved.