Question 1162212
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The function doesn't provide the original average score because you excluded zero from the domain of the function when you specified that *[tex \Large t] is <i><b>strictly</b></i> greater than zero.  Your function is not defined at *[tex \Large t\ =\ 0]


Solve


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 75\ -\ 6\frac{\log(t\,+\,1)}{\log(e)}\ =\ 61.2]


for *[tex \Large t]


By the way, the next time you want to use this model, use the natural logs.  Simpler formula:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(t)\ =\ 75\ -\ 6\cdot\ln(t\,+\,1)]

								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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