Question 1162221
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<pre>

{{{3^x}}} + {{{3^(x+1)}}} = {{{11^x}}} + {{{11^(x+1)}}}


{{{3^x*(1+3)}}} = {{{11^x*(1+11)}}}


{{{4*3^x}}} = {{{12*11^x}}}


{{{3^x/11^x}}} = {{{12/4}}}


{{{(3/11)^x}}} = 3


Take logarithm base 3 of both sides


{{{x*log(3,(3/11))}}} = {{{log(3,(3))}}}


{{{x*(1-log(3,(11)))}}} = 1


x = {{{1/(1-log(3,(11)))}}}.      <U>ANSWER</U>
</pre>


Solved.