Question 1162201
<br>
There are a wide variety of very different methods for solving problems like this; different methods will work better for different people.<br>
I will show you the method that works best for me.<br>
Start with the given numbers and change two numbers at a time, using common sense, until you have the desired numbers.<br>
6 wolves, 6 days, 6 sheep  [given]<br>
60 wolves, 6 days, 60 sheep  [it will take 10 times as many wolves to eat 10 times as many sheep in the same 6 days]<br>
6 wolves, 60 days, 60 sheep  [it will take 1/10 as many wolves to eat the same 60 sheep if there are 10 times as many days]<br>
ANSWER: It takes 6 wolves to eat 60 sheep in 60 days.<br>
Of course, you can make the jump directly from the given information by changing all three numbers at the same time using logical reasoning:<br>
6 wolves, 6 days, 6 sheep  [given]<br>
6 wolves, 60 days, 60 sheep  [10 times as many sheep to eat, and 10 times as many days, means the same 6 wolves]<br>
Second problem....<br>
6 wolves, 6 days, 6 sheep  [given]<br>
half as many wolves, same number of sheep --> twice as many days:
3 wolves, 12 days, 6 sheep<br>
half as many sheep, same number of wolves --> half as many days:
3 wolves, 6 days, 3 sheep<br>
--------------------------------------------------<br>
Many students find it easy to show the work for this method of solving the problem with a table.<br>
First problem....<br><pre>
   wolves  sheep  days
  ---------------------
      6      6      6
      60     60     6   10 times as many sheep, same number of days --> 10 times as many wolves
      6      60    60   10 times as many days, same number of sheep --> 1/10 as many wolves</pre>