Question 1162180
find a place where the line 2x-1 is tangent to the curve.

Want one point only, where the slopes are the same, 2, because that is the slope of the line
find slope of the quadratic: derivative is 6x+8, and that equals 2 when x=-1
when x=-1, 2x-1=-3
so the point is (-1, -3) for the line.  It has to be for the quadratic as well.
when x=-1, the quadratic is 3-8+k and that has to equal -3
-5+k=-3
k=2

{{{graph(300,300,-2,0,-5,5,3x^2+8x+2,2x-1)}}}