Question 1162122
<pre>
The player can pick all 6 winning numbers in 6C6 = 1 way
The player can pick 5 winning numbers and 1 non-winning number in (6C5)∙(47C1) = 282 ways.

So there are 1+282=283 ways the player could win.

There are 53C6 = 22957480 ways the player could pick 6 numbers.

Probability of winning = 283 ways out of 22957480 or 283/22957480 or about

0.000012327136950571229943356152330308030323885722649001545...

1.2327×10<sup>-5</sup>, which is about 1 chance in 81122.

Edwin</pre>