Question 1161734
The 95% CI half interval is t (0.975, df=48)*s/sqrt (n)
t=2.01
half-interval is 2.01*16.4/7=4.71
add to and subtract from mean
(0.69, 10.11) mg % are units
The CI suggests that there is a positive change since 0 is not in the confidence interval. It would suggest that garlic does help reduce LDL.