Question 107815
{{{(-5x^2yz^3)^5/ (-5x^2yz)}}}  here you can apply the rule:{{{(a^m)^n = a^mn}}}

then you have:


{{{(-5x^10y^5z^15)/ (-5x^2yz)}}} ......now cancel {{{-5x^2yz}}}


{{{x^8y^4z^14}}}