Question 1162022
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Two rules:


1. The SUM of the logs is the log of the PRODUCT


2. The DIFFERENCE of the logs is the log of the QUOTIENT


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log\(\frac{uv}{w}\)\ +\ \log\(\frac{uw}{v}\)\ +\ \log\(\frac{vw}{u}\)\ -\ \log\(uvw\)\ =\]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log\(\(\frac{uv}{w}\)(\frac{uw}{v}\)\(\frac{vw}{u}\)\(\frac{1}{uvw}\)\)\ =]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log\(\(\frac{u^2v^2w^2}{uvw}\)\(\frac{1}{uvw}\)\)\ =\ \log\(\frac{uvw}{uvw}\)\ =\ \log(1)\ =\ 0]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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