Question 1161958
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ x^2\ -\ 3x\ +\ 4]


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(-t)\ =\ (-t)^2\ -\ 3(-t)\ +\ 4]


But if 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(-t)\ =\ 6]


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (-t)^2\ -\ 3(-t)\ +\ 4\ =\ 6]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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