Question 1161934
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Let V be the volume under the problem's question, in cubic centimeters.


Then you have this equation to find V


    0.04*2.5 = 0.002*(V+2.5),


saying that the amount of the inert chemical is the same before and after.


From the equation,


    V = {{{(0.04*2.5- 0.002*2.5)/0.002}}} = {{{(0.1 - 0.005)/0.002}}} = {{{0.095/0.002}}} = {{{95/2}}} = 47.5 cm^3.     <U>ANSWER</U>
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Solved.