Question 1161899
95% CI half-interval is z*sqrt(p*(1-p)/n) where z=1.96 and p=0.42
so the half-interval is 1.96 *sqrt(.42.*58/1500)
=0.025
the CI is p hat+/- half-interval or (0.395, 0.445)

Go to STAT TESTS A ENTER and put in 630 1500 and 0.95 for CI and ENTER.  The 630 comes from 1500*0.42, the number of people who stated they favored.