Question 1161789
Find the acute angle that the curve y=1-3x^3 cut the x-axis.
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Find the x-intercept
3x^3 = 1
{{{x = root(3,1/3)}}}
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Find the slope at {{{x = root(3,1/3)}}}
y' = -9x^2
y' = {{{-9*root(3,1/9)}}}
y' =~ -4.3267 at y = 0 = tangent of the angle
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Angle =~ 76.986 degs