Question 1161760


total {{{10}}}

{{{2}}} black, {{{3}}} white, and {{{5}}} red

 The probability of selecting {{{three}}}{{{ red}}} beads without replacemen:


to choose {{{one}}} red bead :{{{5/10=1/2}}}

After the first bead  is drawn, there are  {{{2}}} black, {{{3 }}}white, and{{{ 4 }}}red beads in the bag, total {{{9}}}

The probability of drawing a {{{second}}} red bead is  {{{4/9}}}.

After the second bead  is drawn, there are  {{{2}}} black, {{{3}}} white, and {{{3}}} red beads in the bag, total {{{8}}}

The probability of drawing a {{{third}}}red bead is  {{{3/8}}}.

then the probability of selecting three red beads is:

{{{ (1/2)(4/9)(3/8)=1/12=0.08333333333333333}}}


so, answer is {{{0.083}}}