<PRE><B>Question 1161722</B>
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&lt;pre&gt;

The total hourly wage over 4000 employees at the first division is  4000*6.05 dollars.


The total hourly wage over 8000 employees at the second division is  8000*7.39 dollars.


The total hourly wage over all 4000+8000 = 12000 employees at the both division is  4000*6.05 + 8000*7.39 dollars.


The average hourly wage over all 12000 employees at both divisions is  


    {{{(4000*6.05 + 8000*7.39)/(4000+8000)}}} = 6.94 dollars.     &lt;U&gt;ANSWER&lt;/U&gt;
&lt;/pre&gt;

Solved.


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