Question 1161600
<i><b>a. Between 476 and 500 passengers</i></b>
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z1 = {{{(476-476)/22}}} = {{{0/22}}} = 0
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Look up 0 on a z-table.  The result is 0.5000.
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z2 = {{{(500-476)/22}}} = {{{24/22}}} = 1.09
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Look up 1.09 on a z-table.  The result is 0.8621.
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Subtract 0.5000 from 0.8621 to get a result of <b>0.3621</b>.
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<i><b>b. Less than 450 passengers</i></b>
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z = {{{(450-476)/22}}} = {{{(-26)/22}}} = -1.18
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Look up -1.18 on a z-table.  The result is <b>0.1190</b>.
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<i><b>b. More than 510 passengers</i></b>
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z = {{{(510-476)/22}}} = {{{34/22}}} = 1.55
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Look up 1.55 on a z-table.  The result is 0.9394.  This is the probability that FEWER than 510 passengers are on the train.  So, the probability that MORE than 510 passengers are on the train is 1 - 0.9394...or, <b>0.0606</b>.