Question 1161519
<pre>
{{{y-y[1]=m(x-x[1])}}}

Where {{{(matrix(1,3,x[1],",",y[1]))}}}{{{""=""}}}{{{(matrix(1,3,2,",",-4))}}}

and 

{{{m=3/5}}}

{{{y-(-4^"")=expr(3/5)(x-(2)^"")}}}

{{{y+4=expr(3/5)(x-2^"")}}}

Multiply both sides by 5 to clear the fraction:

{{{5(y+4^"")=5*expr(3/5)(x-2^"")}}}

{{{5y+20=3(x-2^"")}}}

{{{5y+20=3x-6}}}

Add -20 to both sides:

{{{5y+20-20=3x-6-20}}}

{{{5y=3x-26}}}

ADD -3x to both sides:

{{{-3x+5y=-3x+3x-26}}}

{{{-3x+5y=-26}}}  <--the other tutor left it this way, but standard form
                     requires that the first term be positive.

Divide through by -1 to make the term in x positive:

{{{3x-5y= 26}}}

Edwin</pre>